Refer to the exhibit. A computer that is configured with the IPv6 address as shown in the exhibit is unable to access the internet. What is the problem?
- The gateway address is in the wrong subnet.
When subnetting a /64 IPv6 network prefix, which is the preferred new prefix?
- /72
Which two notations are useable nibble boundaries when subnetting in IPv6? (Choose two.)
- /64
- /68
Open the PT Activity. Perform the tasks in the activity instructions and then answer the question.
What issue is causing Host A to be unable to communicate with Host B
- Host A and host B are on overlapping subnets
Consider the following range of addresses:
2001:0DB8:BC15:00A0:0000::
2001:0DB8:BC15:00A1:0000::
2001:0DB8:BC15:00A2:0000::
...
2001:0DB8:BC15:00AF:0000::
The prefix for the range of addresses is __________________
- /60
Fill in the blank.
In dotted decimal notation, the subnet mask_________ will accommodate 500 hosts per subnet.
- 255.255.254.0
Given the network address of 192.168.5.0 and a subnet mask of 255.255.255.224, how many addresses are wasted in total by subnetting each network with a subnet mask of 255.255.255.224?
- 72
In a network that uses IPv4, what prefix would best fit a subnet containing 100 hosts?
- /25
Which two reasons generally make DHCP the preferred method of assigning IP addresses to hosts on large networks? (Choose two.)
- It eliminates most address configuration errors
- It reduces the burden on network support staff
Fill in the blank.
In dotted decimal notation, the IP address_______ is the last host address for the network 172.25.0.64/26.
- 172.25.0.126
When developing an IP addressing scheme for an enterprise network, which devices are recommended to be grouped into their own subnet or logical addressing group?
- hosts accessible from the internet
Refer to the exhibit. How many broadcast domains are there?
- 4
How many usable host addresses are there in the subnet 192.168.1.32/27?
- 30
A nibble consists of _______ bits
- four
How many host addresses are available on the network 172.16.128.0 with a subnet mask of 255.255.252.0?
- 1022
A network administrator needs to monitor network traffic to and from servers in a data center. Which features of an IP addressing scheme should be applied to these devices?
- predictable static IP addresses for easier identification
How many bits must be borrowed from the host portion of an address to accommodate a router with five connected networks?
- three
Refer to the exhibit. The network administrator has assigned the LAN of LBMISS an address range of 192.168.10.0. This address range has been subnetted using a /29 prefix. In order to accommodate a new building, the technician has decided to use the fifth subnet for configuring the new network (subnet zero is the first subnet). By company policies, the router interface is always assigned the first usable host address and the workgroup server is given the last usable host address. Which configuration should be entered into the properties of the workgroup server to allow connectivity to the Internet?
- IP address: 192.168.10.38 subnet mask: 255.255.255.248, default gateway: 192.168.10.33
What is the subnet address for the address 2001:DB8:BC15:A:12AB::1/64?
- 2001:DB8:BC15:A::0
Refer to the exhibit. A company uses the address block of 128.107.0.0/16 for its network. What subnet mask would provide the maximum number of equal size subnets while providing enough host addresses for each subnet in the exhibit?
- 255.255.255.128
A company has a network address of 192.168.1.64 with a subnet mask of 255.255.255.192. The company wants to create two subnetworks that would contain 10 hosts and 18 hosts respectively. Which two networks would achieve that? (Choose two.)
- 192.168.1.64/27
- 192.168.1.96/28
A network administrator is variably subnetting a network. The smallest subnet has a mask of 255.255.255.248. How many host addresses will this subnet provide?
- 6
Refer to the exhibit. Match the correct IP address and prefix that will satisfy the usable host addressing requirements.
- Network A needs to use 192.168.0.0 /25 which yields 128 host addresses.
- Network B needs to use 192.168.0.128 /26 which yields 64 host addresses.
- Network C needs to use 192.168.0.192 /27 which yields 32 host addresses.
- Network D needs to use 192.168.0.224 /30 which yields 4 host addresses.
Match the subnetwork to a host address that would be included within the subnetwork
- Subnet 192.168.1.32/27 - 192.168.1.48
- Subnet 192.168.1.64/27 - 192.168.1.68
- Subnet 192.168.1.96/27 - 192.168.1.121
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